javascript - Prevent nested label link from following, but change checkbox state -

-

मेरे पास एक ऐसा मुद्दा है जहां मेरे पास निम्न मार्कअप है: 

  & lt; input type = "चेकबॉक्स" id = "foo" / & gt; & Lt; लेबल = "foo" & gt; के लिए & Lt; a href = "http://www.google.com" & gt; चेकबॉक्स पाठ & lt; / a & gt; & Lt; / लेबल & gt;   
 उपयोगकर्ता के पास जावास्क्रिप्ट सक्षम नहीं होने पर लेबल में नेस्टेड एंकर हैं, और उस स्थिति में वे लेबल पर क्लिक करते समय लिंक का पालन करेंगे।  
 I चेकबॉक्स स्थिति को बदलते समय लिंक को क्लिक करने और एक चेतावनी दिखाने के लिए निम्नलिखित जावास्क्रिप्ट / jQuery हैं:  
  $ (फ़ंक्शन () {$ ("लेबल")। क्लिक करें (फ़ंक्शन (E) {e.preventDefault ();}); $ ("# foo")। परिवर्तन (फ़ंक्शन () {चेतावनी ("चेकबॉक्स बदल गया");});});   
  
 हालांकि लेबल पर क्लिक करने पर चेकबॉक्स को चिह्नित स्थिति परिवर्तित नहीं होती है।  
 मुझे पता है कि मैं  hack < / Em> कोड की जाँच करें और चेक की गई स्थिति को सेट करने के लिए कोड को जोड़कर मूल ब्राउज़र की कार्यक्षमता का प्रयास करें और उसका अनुकरण करें, हालांकि मैं इसे अनुकूलन की तुलना में देशी कार्यक्षमता का उपयोग करना पसंद करूंगा।  
 मैं कैसे चेकबॉक्स बदल सकता हूं राज्य को लिंक का पालन किए बिना, और जावास्क्रिप्ट का उपयोग करके चेक किए गए राज्य को स्थापित किए बिना?   
 
 
 बिट यहाँ उलझन में  और जावास्क्रिप्ट का उपयोग करके चेक किए गए राज्य को निर्धारित किए बिना?  ... लेकिन मुझे लगता है कि आप  ट्रिगर ()  ...  
  $ ("label $ Foo.attr ("चेक किया हुआ",! $ Foo.attr ("चेक किया गया")); $ foo.trigger (' परिवर्तन '); वापसी वापस;});

Comments

Post a Comment

Popular posts from this blog

php - How to filter values fetched from database on the basic of comma included? -

-
Image
I have some values ​​in my database in the column, as I have been shown in the picture below, Now if you notice there over there In the position of number three, we have the value, which is Italian, pizzeria (pizza), there may be some other values ​​that can be included in the Italian, pizzeria (pizza) like COMMA (,) Yes, as we can see in the picture below, Now I want to get all the values ​​of php (select * from tablename), but if the value is included in COMMA, then I Any way to filter out? I just want to select values ​​that do not have any commas, thanks in advance? Unless there is a pregate in my knowledge, or an array filter can help. would not like predicate: Choose * Where 'Business' food is not like '%,%' from the tablet name;
Read more

excel vba - How to delete Solver(SOLVER.XLAM) code -

-
After opening several examples of macro / code written, I suddenly get stuck with a code that seems safe. Solver (SOLVER.XLAM) is doing this notation and I would like to remove it from my system. I do not think this is a relativant code. Can anyone tell me what should I do? I have already installed something to remove the password but Solver is still asking for password and I can not get rid of it! itemprop = "text"> Solver Excel is add-in If you want to delete it, then Excel Application & gt; Options & gt; Add-ins & gt; Search for 'Go to' button and gt; Uncheck the solver on the list like press something (I can not give you the exact path because I have the Polish version of Excel). Trying to open Solver's VBA code is not good because it There is allegedly copyright. Besides, I do not think Solver creates any disadvantages while working with Excel or VBA.
Read more

c# - Add Image in a stackpanel based on textbox input -

-
I am trying to store the image in a stapple panel .. \ resources \ ebi.png Most of the time, the textbox input Based on "Atracount", the same image will be displayed in the StackPanel below, the sample code has been attempted, but it is getting an error saying "The specified view is already visible to any other view Has a child or is the origin of a composition goal " is the code below The Oshis: private bitmap image bmp = new Bitmap image (new Uri ( "WpfApplication1; components / resources / ebi.png", Urikind. Riletiv Orsolut)); Private Zero EtReqCount_TextChanged (Object Sender, TextChangedEventArgs E) {StackPanel dynamicStackPanel = new StackPanel (); DynamicStackPanel.Width = 300; DynamicStackPanel.Height = 200; DynamicStackPanel.Background = New SolidColorBrush (Color. LightBu); DynamicStackPanel.Orientation = Orientation. Vertical; If (Attarcount.Text! = "") {For (int k = 1; k & lt; = int32.Parse (etReqCount.Text); k ++) {I...
Read more