linux - Grep an XML file for certain patterns -

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I have a large XML file that has thousands of elements the same elements: 

  & lt ; RootElem & gt; & Lt; Filoj buzz = "true" & gt; 234 & lt; / Fizz & gt; & Lt; Fizz buzz = "false" & gt; 384 & lt; / Fizz & gt; & Lt; Philos buzz = "true" & gt; & Lt; / Fizz & gt; & Lt; Filoz buzz = "true"> 39494   
 I will run a  grep  which will be  & lt; Fizz & gt; Prints prints, which do not contain text / body data (the number between the opening and closing tags). In the example above,  grep  3 and 5th  & lt; Fizz & gt;  will generate 2 lines for elements, which will not contain numeric data, the file name is  phizze_20.xml . I tried to run the following, but it did not work:  
     
  •   grep fizzes_20.xml ">   
  •   Grep fizzes_20.xml "/>    
     Any thoughts? thank you in advanced!   
     
     
     The xmllint command can be used to implement xpath expression tests for empty nodes:  
      $ xmllint --xpath "// fizz [not (text ())]" data.xml & lt; Fizz buzz = "true" /> & Lt; Fizz / & gt; Compiled with   
     update  
      $ xmllint --version xmllint: 20901 threads: threads tree output push reader pattern author SAXv1 FTP HTTP DTDValid HTML Legacy C14N List XPath XPointer XInclude Iconv ISO8859X Unicode Regexps Automata Expr Schemas Schematron Module Debug Zlib Lzma

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