sql - Comparing Supervisor's Salaries -
I am trying to show employees who help at least 25% of their supervisors. So far, I have a code that can show myself to the supervisors, but I'm not sure how to "hold" supervisor salaries:
SELECT TOP (100) PERCENT Firstname + '' * Employee, id, jubilate AS [Job title] as the last name, Straw (round (pay / 12, 2), 12, 2) AS [Monthly Salary] from the employable WHERE (in the id ( Negative WHERE from the Selection Supervisor (not Supervisor)) Last name by order, First name
- First of all, search for employees and supervisors
Emp.id, emp.Salary, Sup.SuperVisor, joining Sup.Salary employeetable emp employeetable emp.supervisor = Sup.id
< Code> where emp.Salary & gt; = .25 * sup.Salary To eliminate those people where there are supervisors
and not emp.id (select different supervisor from employeetable Do)
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