How do I properly scope a Ruby lambda? -

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मेरे पास यह लैम्ब्डा है: 

  echo_word = lambda do | शब्द | शब्दों को many_words = /\wss(.+)/ 2.times do sleep 1 match = many_words.match (शब्द) डालता है [1] यदि मैच की अंत नींद 1 एंड   
 मैं इसे  प्रत्येक  को एक ब्लॉक के रूप में देना चाहता हूं, और भविष्य में कई और अधिक ब्लॉक करना चाहता हूं।  
  def is_there_an_echo_in_here * args args.each और echo_word # फेंकता है नाम त्रुटि का अंत है_तोरे_आ_छोआ_इन_हाँ 'हैलो आउट आउट', 'मज़ेदार बार'   
 लेकिन जब मैं my_funky_lambda.rb को इस लैम्ब्डा पद्धति से चलाता हूं, तो मुझे एक नेमअरेर मिलता है। मुझे यकीन नहीं है कि इस लैम्ब्डा के दायरे के साथ क्या हो रहा है, लेकिन मैं इसे  is_there_an_echo_in_here  से प्राप्त नहीं कर सकता।  
  echo_word  ठीक से है स्कैड और प्रयोग किया जाता है यदि मैं इसे निरंतर  ECHO_WORD  बना देता हूं और इसे इस तरह प्रयोग करता हूं, लेकिन एक अधिक सरल समाधान होना चाहिए।  
 इस परिदृश्य में, एक्सेस करने का सबसे अच्छा तरीका क्या है  echo_word  अंदर से lamba  is_there_an_echo_in_here , उदाहरण के लिए एक मॉड्यूल में इसे लपेटकर, वैश्विक दायरे तक पहुंचने, कुछ और?   
 
 
 रूबी में, नियमित तरीके नहीं हैं बंद। इस कारण से आप  echo_word  अंदर  is_there_an_echo_in_here  नहीं कॉल कर सकते हैं।  
 ब्लॉक बंद हैं, हालांकि। रूबी 2 + में, आप यह कर सकते हैं:  
  define_method (: is_there_an_echo_in_here) ऐसा करें | * आर्ग्स | Args और echo_word एंड   
 एक अन्य तरीका एक कोड के रूप में  echo_word  पास करना होगा:  
  def is_there_an_echo_in_here * args , ब्लॉक args.each और amp; ब्लॉक एंड is_there_an_echo_in_ यहां 'हैलो आउट', 'मज़ेदार टाइम्स', इको_वर्ड

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