Python regex get with zero or more occurences within the pattern -

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I have a working reggae that gives me the results that I want to give, even then it does not require security (stupid Proof)

Let's say I have a reg box that corresponds to some parts of a path: Dev / model / props / furniture / couch / data / fbx "regex = re.compile (" (. +) / Dev / model /(.+)/(.+)/ data / FBX ") m = Regex.search (Path) if m: print m.groups () # ('C: / Projects / foo', 'props / furniture', 'couch')

I want A Any character capable of match up to the following part of the regex will match some or more folders.

Let's say that we define a folder for simplicity in terms of words (letter or none) ending with slash: 

  [ \ W] * /   
 And I want to group zero to ten  
 I had something in my mind (note that this does not work! ):  
  # words matches any number of characters that term ends with zero by ten times ([[\ w] * /] {0,10}) # Slash noise Edit Once: ([[\ w] * /]?   
 Edit:  
 Based on the answer of RedBaron and jamylak I came up with the following: / P> 
  ((?: [: \ W] + /) {0}}   
 This would be a group of three zero events: [w] a With the character ending with 'slash' / '?': In the beginning of the group it is not being sent back from the matching groups. Even then the outer group that connects them, we only get completely grouped results .  
 One with this Atr issue I want to match that I last part probably a file. (That is why it is not finished with slash.) I also like to get it back without the slash behind the regex, but I can also strip the result end easily.  
 Any feedback is highly appreciated. If this is the way to go, then I will add it as an answer.  
 Edit:  
 It is related:  
  UPDATE / EDIT:   
 has been given so far Based on all the answers I have come with many efforts, yet they all become very slow at the end.   Re: Path = "C: / Projects / Foo / Davem / Model / Props / Furniture / Thought / Data / FBX" Reggae = Rie Compile (R "" ((?: ^ (?: [\ W:] + /?) +) | (?: (?:? & Lt; = /) (?: [\ W] + /?) +)) / Dev / model / "" Print 'match', m, m.greaves () and: print 'no match'   'print' search start 'm = regex.search (path) print' searched ' 
 I'm not completely sure how speed it is! Regexp will not contain the  []  regexp group.  
 This will probably work -  
  \ w * / {010}   
 And use only  ()   
  for the group (  
 < Strong> Edit   
 Based on your edited question, I think what you want is that the directory name matches 0-3 events and then the name of a file also matches .  
 Only characters in file names (and optionally three character extensions)  
  ^ ((?: [: \ W] + /) {0}} (\ w + (?: \. \ W {1,3})? $?   
 It is huge but can be broken into two parts  
 This is what you already have  
  ((?: [: \ W] + /) {0}}   
 and what I add  
  (\ w + (:. \ W {1,3})?)?   
 This is an optional filename at the end (if it is not optional then you can remove the last ?  ) The file name can only be made of algebet only or it may extend to maximum 3 characters  
  ^  to add 
 
 
 ] + /) {0}} (\ w + (?: \. \ W {1,3})?)? $ ') & Gt; & gt; My_str =' fwefw / wfwf / wefwf / dde .cdf '> gt; Pat.search (my_str) .groups () (' fwefw / wfwf / wefwf / ',' dde.cdf ')>  My_str =' Fwefw / dde.cdf '>>     / Html>

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