sql - Summing and ordering at once -

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I have a table of commands where I need to know which 3 partners_ID has the largest sum of the sum , And make the three of them the largest from the largest. 

  testdb = # SELECT amount_total, sale_order to partner_id; Zodiac_tools | Partner_id -------------- + ------------ 1244.00 | 93065. 90. 12 3600.00 3 2263.00 | 25,000.00 10 3263.00 | 3 123.00 | 25 5400.00 | 12 (8 lines)   
 Just starting SQL, I am confused ...   
 
 
 consolidated amount  
 If you want to list the cumulative amount, it can be as simple as:  
  SELECT partner_id, sum ( Amount_sun) AS amout_supertotal FROM 1 order by sales order group 2 DESC limit 3;   
 1 in  Group B1  is a numerical parameter, which refers to the position in the  SELECT  list in this case  Only a formal shortcut for the partner_id by the group .  
 This ignores a special case where more than three partners will qualify and (arguably for lack of definition) will arbitrarily raise. / P> 
 Personal Quantity  
  SELECT partner_id, amount_exe sales_order JOIN (SELECT partner_id, on rank) (amount (amount) by DESC) ORDER 2 by Sirius 3) Top 3 Top 3 by Using (partner_id) ORDER RNK;   
 On the other hand, this includes another partner, if more than 3 partners qualify for the top 3. it gives you.               
 Function execute) after the ranks. The  ORDER BY  window is applied after the work and the  LIMIT  is finalized all in one subquery.  
 Then to join the sub-table on this subquiry, so that only the top dogs should remain in the result and in the order by  rnk .  
> Window tasks require PostgreSQL 8.4 or later.  
 It's rather advanced stuff that lets you learn SQL in a few simple ways.

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