java - Is there an equivalent of x++ that can be used in an expression for incrementing by values greater than 1? -

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Apologies for a slightly misleading title.

It is well known that 

  int x = 4; Println (x ++); // print 4 x = 4; Println (++ x); // print 5 using   
, I found that  
  int x = 4; Println (x + = 4); // print 8   
 Will one increase in the above analog X but instead 4 print? Like other assignment operators, the shortcode assignment returns the final value, like  
 
 
. 
 This lets you type  
  x = y = z + = 4;   
 There is no post-shorthand operator that gives original value.

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