arrays - BASH regex matching in if statement -

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I would like to mention now that I am not overwhelmed with either RegEx or BASH, so a debrief explanation would be very appreciated. This way I can learn thanks.

I have given this file a lot below, but basically what I want to do is take an array $ sqldatabases and see which variables have the @ symbol , Then check that specific variable to not include the @ sign, and finally run a mysqldump for that database; the code that I have happened with is currently If statement is lacking filtering forum @ I ([Sqlcount = 0; sqlcount & lt; $ {# sqldatab For ases [@]}; sqlcount ++) 

  source config.sh sqldatabases = (bounty forum @ user donor) $ Sqldatabases [sqlcount] "= ~ * [@] *]] ; "Sqldatabases [sqlcount] = $ {sqldatabases [sqlcount] Sqlcount]} & gt; .backups / $ timedate / MySQL / $ {sqldatabases [sqlcount]} SQL   
 Thank you again for your help, and try to explain every modification in depth.   
 
 
 You have to use the  $ {array [index]}  syntax. And you do not need to match the  *  s to  @  (or use . * @. *  instead):  
  if [["$ {sqldatabases [sqlcount]}" = ~ @]]; Then sqldatabases [sqlcount] = $ {sqldatabases [sqlcount] // [@] "$ {sqldatabases [sqlcount}}" mysqldump # ... file

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