c - making two struct pointers equal -

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So suppose I have a straight pointer called A and struct B: 

  Struct example {// variables and pointers} * A   
 and then I have an indicator of the datatype structure example:  
  struct Example * B = malloc (size (structure example));   
 If I do  
  A = B;   
 Does this arithmetical operation mean that whatever structure P indicator B is indicating what will be the indicator indicator also indicating? I get it from primitive datatype and pointers, but the structure confuses me because they have variables inside them.  
 ap set and everything   
 
 
 Yes, with the following lines of code, A should point to A, B was pointing.  
  / * Define a straight example datatype * / straight example {// variables and pointers}; / * Structure For example, declare A and B as Pointer * / struct example * A; Structure Examples * B; Allocate memory equal to the size of the structure / example and store the address in B * / B = malloc (sizeof (struct example)); / * Copy the address from B to A, so that the same position was pointing to points B / A = B;   
 You should think of pointers as just another  unnatural long  variable that keeps an address for memory, (since the indicator only tells that address ).  
 With just any other variable, you can copy the address stored in each other in a pointer variable.

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