About pointers in C -

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I have started reading some articles about pointers in C and I have found an example that I can not understand I am here. / P>

The example is here:

Here it is:

We see a slightly different problem. We want to have a two-dimensional array, but we do not need the same length of all the rows. What we do, declare an array of indicators. The second row given below declares A as an array of pointers. Each indicator indicates a float. Here is some applicable code: 

  float linear a [30]; Float * A [6]; A [0] = Linear A; / * 5 - 0 = 5 elements in the row * / A [1] = Linear A +5; / * 11 - 5 = 6 elements in the row * / A [2] = Linear A +11; / * 15 - 11 = 4 elements in the row * / A [3] = Linear A +15; / * 21 - 15 = 6 element * / a [4] = Linear A +21; / * 25 - 21 = 4 element * / A [5] = Linear A + 25; / * 30 - 25 = 5 elements * / A [3] [2] = 3.66; / * 3.66 for Linear A [17]; * / A [3] [- 3] = 1.44; / * Linear A [12]; Negative indices are sometimes useful, but avoid using them as much as possible. * /   
 My question is why why  A [0]  is an indicator for only five elements and not all  linearA  , Because the name of the array is an indicator for its first member.  
 and  A [1] = Linear A + 5;  There are 6 elements in a row - for the same reason? Is  A [1]  considered to be an indicator for the 6th member of  linearA ?  
 Can anyone say that where's my fault?   
 
 
 Except for a few exceptions, the first element of an array name array in C is converted into an indicator .  linearA  is an array 30  float  and in expression:  
  a [0] = linear A;   
 It is converted to an indicator on  float .  
  A  An array of indicator 6  name . The element of  a  is the type indicator of the  float . Then there is an indicator for  a [0]  a  float  and not an indicator for an array.  
 and  a [i] [j]  is equal to c  * (a [i] + j)   a [i] [J]  is a  float  (dereferencing an indicator for  float  a  float ).

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