shell - Bash scripting, multiple conditions in while loop -

I am trying to get a general position while using two situations, but different syntax forums, I Error can not stop throwing what I have here:

  while [$ stats -gt 300] -o [$ stats -eq 0]   
 I Also tried:  
  while [[$ stats -gt 300] || || [$ Figures -Ece 0]]   
 ... as well as many other constructions I have to continue this loop, while  $ stats & gt; 300  or  $ stats = 0 .   
 
 
 The right choice (increasing in order of recommendation):  
  Single POSISIS test commander with #Oo operator (now not recommended) # It is strongly recommended to keep quotation free from blank or undefined variables, while ["$ statistics" -gt 300 -o "$ figures" -ece 0] # Two POSIsi joined the list with test orders || # It is strongly recommended to keep quotation from blank or undefined variable while ["$ figures" -gt 300] || ["$ Statistics" -ece 0] # Two hardcore conditional manifestations joined a list || While [[$ figures - gt 300]] || [[$ Figures - EC 0]] # Single bash conditional expression || Operator While [[$ figures - gt 300 || $ Stats -Ece 0]] #bash arithmetic expressions joined in a list || # $ Optional can be interpreted as a single variable only in the form of a string ((Statistics> 300)) ((Statistics == 0)) and finally, a single bash arithmetic expression || Operator # $ Optional can be interpreted as a single variable in the form of a string ((Statistics> 300 || statistics == 0))   
 Some notes: / P> 
  
  [...]]  and  (in ...) is; If the variable is not set, then the value of  -gt  and  -eq  0 will be assumed.   
 
 Using  $  is optional  ((...)), but using it unknowingly errors Can help you avoid it. If  statistics  is not set, then  ((Statistics> 300))  will go to  statistics == 0 , but  (( $ Stats> 300))  will generate a syntax error.