ruby - How can i add parameter to the given url which is dynamic in rails -

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मेरे पास यूआरएल वाला पृष्ठ है 

  http: // localhost: 3000 / athletes / list   
 जब उपयोगकर्ता इस पृष्ठ पर खोज करता है तो यह  
  http: // localhost: 3000 / एथलीट / सूची? First_name = sachin और last_name =   
 जहां उपयोगकर्ता खोज में  प्रथम_नाम  और  last_name  खोज पैरामीटर हैं।  
 मुझे एक लिंक चाहिए  पहले URL के लिए  
  http: // localhost: 3000 / एथलीट / सूची? दृश्य_प्रकार = कुछ  के लिए पैरामीटर में view_type = कुछ यूआरएल   
 2 यूआरएल के लिए  
  http: // localhost: 3000 / एथलीट / सूची? प्रथम_नाम = sachin और last_name = tendulkar & amp; देखने_प्रकार = कुछ   
 मैंने निम्नलिखित की कोशिश की है  
  और "कुछ",: view_type = & gt; 'कुछ'% & gt;   
 लेकिन दोनों यूआरएल के लिए यह यूआरएल  
  http: // localhost: 3000 / athletes / list? View_type = something    
 
 
  और "%" = "कुछ", params.merge (: view_type = & gt; कुछ ')% & Gt; हालांकि   
 हालांकि अधिकांश मामलों में कोड कुछ कारणों से काम करता है, क्योंकि यह कुछ यूआरएल के लिए त्रुटि दे रहा है क्योंकि मैं पूर्व के लिए friendly_url  का उपयोग कर रहा हूं।    
  http: // localhost: 3000 / athlete / sachin_ramesh_tendulkar_1   
 मुझे गलत url के नीचे दे  
  http: // localhost: 3000 / एथलीट / 1? दृश्य_प्रकार = कुछ   
 यह तय करने के लिए कि मैं  javascript  पद्धति का उपयोग कर रहा हूं  
  फ़ंक्शन कुछ () {var par = "" var link = window.location.href यदि (link.indexOf ('view_type = something') == -1) par = link.indexOf ('?' )! = -1? "& Amp; दृश्य_प्रकार = कुछ": "? दृश्य_प्रकार = कुछ" window.location.href = link + par}   
 और रेल कोड  
  & lt; % = Link_to "कुछ", "जावास्क्रिप्ट: शून्य (0)",: onclick = & gt; "कुछ कुछ();" & Gt%;

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