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It seems that assembly language has gone out of fashion somewhat, and thus I have a Sharpier / Source formatting tool Can not find Anyone have any suggestions on this? Search for asm source erotic , there is a lot of them ... maybe emacs can also be used with its many editing modes and indent-field macros Can help.

I am using TaffyDB for "DB" for that website, which I am currently working on. Its pretty clean, I can do 'like' searches, however, 'like' search is still sensitive and if there is a record: "banana", a question of "banana" will fail. Nobody knows how to use TaffyDB for such a question Or, there is a JS DB that can do such a function Just use likenocase : Db ({title: {"likenocase": Val}}) .order (...

The service stack support model is in Swagger in the sample code below [root (Root "(" / user "," post, put ", summary =" create a new user ")] [root (" / user "," GET ", summary =" make available to all users " User / {id} "," GET ", summary =" Get user with specific ID ")] Public class users: request buzz, erranton & lt; UserResponse & gt; {{Apamemel (name = "id", description = "user id", parameter type = "path", datatype = "int", iiReaded = falls}] public entry id {received; Set; } [Apemail (name = "user data", description = "user data", parameter type = "body", datatype = "complex", iiReaded = false)] public user entry {get; Set; }} I should have a complex type or container type of user data. However, if I define it to be one of them, then all I get in SwaggerUI is a text field box. I do not get t...

I have a report on Java that I am working in Java. In Java, I can dynamically populate a bean with the data with the following code: list & gt; ThemeBean & gt; Theme = New Arreelist & gt; ThemeBean & gt; (); CSVReader csvReader = new CSVReader (new FileReader (csvFilename)); & Lt; String [] & gt; Data = csvReader.readAll (); (String [] D: data) {Themebeam TB = new themeben (); Tb.setThemes (d [0]); Tb.setComments (d [1]); Tb.setSentiment (d [2]); Themes.add (TB); } Jasper Design jasperDesign = JRXmlLoader.load (fileName); JRBeanCollectionDataSource DS = new JRBeanCollectionDataSource (themes); JasperReport jasperReport = JasperCompileManager.compileReport (Jasper Design); JasperPrint jasperPrint = JasperFillManager.fillReport (Jasperport, Blank, DS); This works fine when the correct fields in the .jrxml file are specified and the textFieldExpression is within the tag ... The following dynamically generated list was made: & lt; TextFieldExpre...

I want to change the part of the URL with javascript but stupid Rijks is giving me a headache. I want to switch from: http://website.com/test.html/post/something-else/ do this For: http://website.com/post/something-else/ Any ideas? Thanks! Use the Change () function var url = ' Http://website.com/test.html/post/something-else/ 'url = url.replace (' / test.html ',' ') console.log (url) // "http: // Website Com / Post / something-else / "

After clicking the user clicks, I try to play a clip in one continuous loop after the other trying to get the video player I am here. Even I have so far code: Var Videoplayer = document.getElementById ('Video'); VideoPlayer.onend = function () {videoPlayer.src = "http://www.mp4point.com/downloads/8feeca1a540b.mp4"; } JSField: This works: var video player = document.getElementById ('video'); VideoPlayer.addEventListener ('Finished', function () {this.pause (); this.src = "http://www.mp4point.com/downloads/8feeca1a540b.mp4";}, false); Updated wired:

मेरे पास निम्न C # कोड है: AddCommentForm = string.Format ("& lt; Form name = \ "addcomment \" method = \ "post \" runat = \ "server \" id = \ "add_comment_form \" & gt; & lt; पी & gt; TITLE: & lt; इनपुट प्रकार = \ "text \" name = \ "शीर्षक \" / & gt; & lt; / p & gt; & lt; p & gt; कंटेंट & lt; textarea नाम = \ "सामग्री \" & gt; & lt; / textarea & gt; & lt; / p & gt; & lt; पी & gt; & lt; बटन प्रकार = \ " \ प्रस्तुत "& gt; सबमिट करें और lt; / बटन & gt; & lt; / p & gt; & lt; / प्रपत्र & gt;"); This.Form.Action = "ViewArticle.aspx? ArticleID =" + अनुच्छेद; समस्या यह है कि दूसरी पंक्ति में एक त्रुटि है: System.NullReferenceException पकड़ा गया मेरा प्रश्न यह है कि मैं यह त्रुटि कैसे कर सकता हूं? और यह कोड क्यों काम करता है? & lt;% this.Form.Action = "ViewArticle.asp...